Get Current Directory in java using getAbsolutePath() This sample java source code demonstrates usage of getAbsolutePath() in getting the current directory.
One other solution is get it using the System.getProperty. Basically we will explore getAbsolutePath() method of File class under java.lang package.
Java get file path directory how to#
Then these path names are displayed using the methods java.io.File.isFile() and java.io.File.isDirectory() that specify whether they are files or directories. In this section we will be showing examples on how to get the current directory in java. The method java.io.File.listFiles() is used to obtain the contents of the directory "C:\JavaProgram". The output of the above program is as follows − Output C:\JavaProgram\D is a directory In this tutorial, we'll learn how to get the current working directory in Java with, java.io.File,, and. This method requires no parameters and it returns the abstract path names that specify the files and directories in the required directory.Ī program that demonstrates this is given as follows − Example import java.io.File įile directory = new File("C:\JavaProgram") It's an easy task to get the current working directory in Java, but unfortunately, there's no direct API available in the JDK to do this. To get the user’s home directory, we need to use the string USERPROFILE. We need to pass the name of the environment variable that we want to access.
The getenv () method of the System class is used to get the value of system environment variables. The contents of a directory can be obtained using the method java.io.File.listFiles(). Get the User’s Home Directory Using the System.getenv () Method in Java.
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